Besi yang massa nya 4 kg suhu nya 20°c dipanaskan dengan kalor 92 kilo joule. apabila kalor jenis besi 460j/kg°c, maka suhu besi setelah di panaskan adalah....
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Diketahui :
massa (m) = 4 Kg
Kalor jenis (c) = 460J/kg°c
Kalor (Q) = 92 KJ = 92.000 J
Suhu awal ([tex] \rm{t}_{2}[/tex]) = 20 C°
[tex]~[/tex]
Ditanya :
Suhu akhir ([tex]\rm{t}_{2}[/tex])
[tex]~[/tex]
Jawab :
[tex]\rm Q = m \times c \times ΔT[/tex]
[tex]\rm 92.000 = 4 \times 460 \times ({t}_{2} - {t}_{1})[/tex]
[tex]\rm 92.000 = 1.840 \times ({t}_{2} - 20)[/tex]
[tex]\rm( {t}_{2} - 20) = \dfrac{92000}{1840}[/tex]
[tex]\rm {t}_{2} - 20 = 50[/tex]
[tex]\rm{t}_{2} = 50 + 20[/tex]
[tex]\rm{t}_{2} = \red{ \bold{70}}[/tex]°
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@Kaisa9
Kalor
Diketahui:
- m = massa = 4 kg
- c = kalor jenis = 460 J/kg°C
- T1 = suhu awal = 20°C
- Q = kalor = 92 kJ = 92.000 J
Ditanya:
- T2 = suhu akhir ?
Jawaban
Q = m × c × ΔT
Q = m × c × (T2 - T1)
92.000 = 4 × 460 × (T2 - 20)
92.000 = 1.840 × (T2 - 20)
(T2 - 20) = 92.000/1.840
(T2 - 20) = 50
T2 = 50 + 20
T2 = 70°C ✔
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